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Surface of Revolution

 

Motivation:

 

                     In the previous section, the length of a curve y=f(x) can be obtained via the integral

                                                    

 

 

                    We might think a little further:  if  we rotate the curve along the x-axis, the surface spanned by the length of the curve, denoted as ds ,  is with area

 

                                                        2  yds

                         and previously we have

                                                        ds=

                                                           =

 

                                               

 

                         So,  the surface area of the infinitesimal ring is

 

                                        dA = 2  yds

                                              = 2  y

 

                       To sum up those small pieces of rings,  the total area spanned from x=a to x=b is

 

                                        A =

                                           =

 

                     This is our “intuitive” result and there could be other ways to find the surface area of a object; or this method might fail to apply on some cases.  Thus, we need to think about the condition that every step can hold.  The simplest conjecture is that f(x) is differentiable – that can make sure the existence of the derivative function and continuity of the curve.

 

 

 

 

Theorem ( Surface Area of Revolution )

             Let  y= f(x) be a differentiable function on [a,b] .  Then the surface generated by rotating the curve y= f(x) along x-axis is with area

 

                                            A=

 

 

 

 

 

Example ( Surface Area of  Sphere )

                E: x2 + y2 = r2 , r > 0 .  Find the surface area by rotating E along x-axis.

 

         Sol:

                           It is only necessary consider the effect by rotating

                                                       y= f(x) =

 

                           Then

                                              f’(x) =

                                            A=

                                               =

                                               = 4  r2

 

 

 

 

 

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