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Monotone Function and Its Derivative
Motivation: For a function f(x), it is known that its derivative function is defined as
If the value of this limit is larger or smaller than 0, what would the function look like? That is the topic we are going to explore here.
Definition ( Monotone Function ) Let f(x) be a function of x. f(x) is known as increasing ( or monotonically increasing ) if
f(a) f(b) for any a < b .
Similarly, f(x) is known as decreasing ( or monotonically decreasing ) if
f(a) f(b) for any a< b .
If the “equality” is removed in the statement above, it is known as “strictly increasing or strictly decreasing” function.
Theorem If f’(x) > 0 for x [a,b] , then f(x) is monotonically increasing in the interval [a,b] .
Proof: Let d [a, b] and f’(d) = c > 0 . So, for any >0 , there exists > 0 such that
< when | h| < c - < < c + when |h| < Since c>0, we can choose small enough such that c- > 0.
So, if h > 0, 0 < h (c - ) < f(d+h) – f(d)
if h < 0, f(d+h) –f (d) < h ( c - ) < 0
Then in the small neighborhood of d , f(x) is monotonically increasing. And this holds for every point in the interval [a,b] because f’(x) > 0 in this interval. So, f(x) is monotonically increasing in this interval.
Example: f(x)=x2 – 2x-3
f’(x) = 2x -2 Thus, when x > 1, f’(x) > 0 ; when x< 1, f’(x) < 0 . Roughly speaking, f(x) should look like as follows:
While x< 1, f(x) is decreasing ; while x>1, f(x) is monotonically increasing.
Example: f(x)=x3 -2x2 -4x+1
f’(x) = 3x2 – 4x -4 = (3x+2)(x-2)
When x < - , f(x) is monotonically increasing because f’(x) > 0 . When - < x < 2 , f(x) is monotonically decreasing because f’(x) < 0; When x > 2, f(x) is monotonically increasing because f’(x) > 0.
Example: f(x) = ln(x) where x > 0 .
f’(x) = > 0 for x > 0 .
Thus, f(x) is monotonically increasing in its domain.
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