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Derivative of Logarithm Function
Motivation:
f(x)=log(x), where x > 0 . Similarly, let’s start with the basic definition to find its derivative.
(log(x+h) – log(x)) = log( ) = log( 1 + ) = log( 1 + )
Up to this point, we find out it is difficult to go on. Let’s see if we can transform it to other form: log( 1 + ) =
If the limit of exists when , then we can get a significant result. Otherwise, we need to find some other methods to find the derivative of f(x). To find the limit of exists as , the problem is equivalent to the following one:
(1+ )n as n
Theorem ( Euler Number and Euler Series) : The limit of (1+ )n exists as n .
Proof: We use binomial theorem to represent it in the following way:
(1+ )n = 1+ n( ) + ( )2 + ( )3+ …+ ( )n 1 + 1 + + + … +
And when we introduced Cauchy Criterion, we have seen that this series converges. It also can be proved by using ratio test. Thus, (1+ )n has a upper bound. On the other hand,
(1+ )n = 1+ n( ) + ( )2 + ( )3+ …+ ( )n 1 + 1 + ( )2 + … + ( )k when k < n. The inequality holds by dropping some tailed positive terms. Thus, for n goes to infinity,
(1+ )n 1+1+ + + … + for any k< n .
So, (1+ )n converges to 1 + 1 + + + … + as n . Usually, we denote this number as
e = = 2.71828…
Derivative of Logarithm Function
Let’s continue the previous work.
(log(x+h) – log(x)) =
If we choose e as the base of the logarithm function, and
= e then the result can be greatly simplified. And we denote the logarithm function by using the base e as “ln”; e is known as the base of natural logarithm.
So, for x>0,
=
Theorem: Let f(x)=logax , a 1, x > 0 . Then f’(x)=
Proof:
f(x)= logax =
Thus, f’(x) = .
Example: Find the derivative function of f(x)=ln(2x2+1)
Sol: By chain rule, we have f’(x) = (4x) =
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